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bakshish    
n. 津贴;小帐

津贴;小帐

bakshish
n 1: a relatively small amount of money given for services
rendered (as by a waiter) [synonym: {gratuity}, {tip},
{pourboire}, {baksheesh}, {bakshish}, {bakshis},
{backsheesh}]


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  • How do you solve #\sqrt { 0. 25} \times \sqrt { 2}#? - Socratic
    See a solution process below: Use this rule for multiplying radicals: sqrt (color (red) (a)) * sqrt (color (blue) (b)) = sqrt (color (red) (a) * color (blue) (b
  • How do you simplify #sqrt (512k^2)#?? - Socratic
    To simplify this, it is helpful to split up what we have sqrt (512k^2)=sqrt (512)*sqrt (k^2) We can see that the second part becomes just k Let's look at sqrt (512) and try to find factors that multiply to give 512 Well, let's start by dividing by 2 512 2=256 256 is a perfect sqaure! It has factors 16*16 However, 512 is not a perfect square
  • How do you simplify 2 the square root of 5? - Socratic
    Explanation: To rationalize the denominator of a fraction you can multiply both numerator and denominator by #sqrt (5)#
  • What is the square root of 20 ? + Example - Socratic
    Explanation: #sqrt (20) = sqrt (2^2 * 5) = 2 sqrt (5)# This is an irrational number somewhere between #4 = sqrt (16)# and #5 = sqrt (25)# We can get rational approximations to it in a variety of ways For example:
  • How do you simplify sqrt392? | Socratic
    14sqrt(2) When simplifying roots of Natural numbers it is often useful to express the number as the product of prime numbers Note: 392 = 2xx2xx2xx7xx7 Therefore: sqrt(392) = sqrt(2xx2xx2xx7xx7) For every pair of prime factors can then be taken through the sqrt as follows: sqrt(392) = 2xx7xxsqrt(2) sqrt(392) = 14sqrt2
  • How do you rationalize the denominator and simplify #sqrt (10 2)#?
    sqrt5 >"simplify by dividing the values inside the radical" rArrsqrt (10 2)=sqrt5larrcolor (blue)"in simplest form"
  • What times the square root of 2 equals 30? - Socratic
    15sqrt2 >"let x be the multiplier we require to find" rArrx xxsqrt2=30 rArrx=30 sqrt2 color (blue)"rationalise "" the denominator by multiplying both" "the numerator and denominator by "sqrt2 "this means eliminating the radical from the denominator" [sqrtaxxsqrta=a]larrcolor (blue)"note" rArr (30) sqrt2xxsqrt2 sqrt2 = (30sqrt2) 2=15sqrt2
  • In the set of real numbers, what is the domain of f(x)=sqrt(x+5 . . .
    The domain, or allowed values of x, is x>=-5 In interval notation, the domain is [-5,oo) For real numbers, the expression under the square root must be greater than or equal to zero In other words, you can't take a square root of a negative f (x)=sqrt (x+5) x+5 >= color (white)a0 color (white) (a)-5color (white) (a^2)-5color (white) (aaa)Subtract 5 from both sides color (white) (aa)x>= -5
  • Question #71971 - Socratic
    22 4% The relation between kinetic energy K and momentum p of an object is p=sqrt (2mK) where m is the mass of object First let momentum is p_1=p=sqrt (2mK) and Kinetic Energy K_1=K Now Kinetic Energy of Body is increased by 50%
  • How do you simplify \sqrt { \frac { 144} { 36} }? | Socratic
    Explanation: #sqrt(144 36)# =#sqrt4# =#+-2# Answer link Related questions How do I determine the molecular shape of a molecule?





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